2x-3x^2/2=5

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Solution for 2x-3x^2/2=5 equation: 



2x-3x^2/2=5

We move all terms to the left:

2x-3x^2/2-(5)=0

We multiply all the terms by the denominator


-3x^2+2x*2-5*2=0

We add all the numbers together, and all the variables

-3x^2+2x*2-10=0

Wy multiply elements

-3x^2+4x-10=0

a = -3; b = 4; c = -10;
Δ = b2-4ac
Δ = 42-4·(-3)·(-10)
Δ = -104
Delta is less than zero, so there is no solution for the equation

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